Sferik sistem
tenzoru tap sferik sisteмde? HƏLLİ
kovariant ∇ (aij ei ej) = (∂aij/∂xkei ej + aij ∂ ei/∂xk ej + aij ei ∂ ej/∂xk) ek = (∂aij/∂xk + Γimk amj + Γjmk aim ) e< /b>i ej ek,
откуда
aij,k = ∂aij/∂xk + Γimk amj + Γjmk aim.Radius vektor r = xi + yj + zk = i x1sin(x2)cos(x3) + j x1sin(x2)sin(x3) + k x1cos(x2).Bazis vektoru tapıriq e1 = ∂r/∂x1 = i sin(x2)cos(x3) + j sin(x2)sin(x3) + k cos(x2),
e2 = ∂r/∂x2 = i x1cos(x2)cos(x3) + j x1cos(x2)sin(x3) - k x1sin(x2),
e3 = ∂r/∂x3 = -i x1sin(x2)sin(x3) + j x1sin(x2)cos(x3). ∂e1/∂x1 = 0,
∂e2/∂x2 = -i x1sin(x2)cos(x3) - j x1sin(x2)sin(x3) - k x1cos(x2) = — (1/x1)e1,
∂e3/∂x3 = -i x1sin(x2)cos(x3) - j x1sin(x2)sin(x3) = -sin(x2) (e1 x1 sin(x2) + e2 cos(x2)),
∂e1/∂x2 = ∂e2/∂x1 = i cos(x2)cos(x3) + j cos(x2)sin(x3) - k sin(x2) = (1/x1)e2,
∂e1/∂x3 = ∂e3/∂x1 = -i sin(x2)sin(x3) + j sin(x2)cos(x3) = (1/x1)e3,
∂e2 /∂x3 = ∂e3/∂x2 = -i x1cos(x2)sin(x3) + j x1cos(x2)cos(x3) = ctg (x2) e3. Simvol Kristof Γ122 = -x1; Γ133 = -x1sin2(x2); Γ233 = -sin(x2)cos(x2); Γ212 = Γ221 = Γ313 = Γ331 = 1/x1; Γ332 = Γ323 = ctg (x2), (2) Tj∂Ti/∂xj = (1/2)∂(TjTj) + εsjk∂Tk/∂xj εisrTr. (1 bu tenliyden εsirεsjk = δijδrk — δikδjr, tapırıq εsjk∂Tk/∂xj εisrTr = — εsir εsjk ∂Tk/∂xj Tr = — (δijδrk — δikδjr ) ∂Tk/∂xjTr = -∂Tk/∂xiTk + ∂Ti/∂xjTj = -(1/2)∂(TjTj) + Tj∂Ti/∂xj, yəni Tj∂Ti/∂xj = (1/2)∂(TjTj) + εsjk∂Tk/∂xj εisrTr. (1
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